t^(-5/2)=32

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Solution for t^(-5/2)=32 equation: 


D( t )

t < 0

t = 0

t < 0

t = 0

t = 0

t in (0:+oo)

t^(-5/2) = 32 // - 32

t^(-5/2)-32 = 0

1*t^(-5/2) = 32 // : 1

t^(-5/2) = 32

-5/2 < 0

1/(t^(5/2)) = 32 // * t^(5/2)

1 = 32*t^(5/2) // : 32

1/32 = t^(5/2)

t^(5/2) = 1/32 // ^ 2

t^5 = 1/1024 // ^ 1/5

t = 1/4

t = 1/4

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